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sin(A-B)=sinAcosB-cosAsinB geometrical proof (video)

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Tiago
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sin(A-B)=sinAcosB-cosAsinB geometrical proof (video) Oct 1, 2017 21:12:46 GMT

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Post by Tiago on Oct 1, 2017 21:12:46 GMT

Hello, it's Tiago again! In this video I demonstrate how to derive sin(A-B)=sinAcosB-cosAsinB from absolute scratch - by geometrical means. Feel free to leave feedback and questions below. Thanks for watching!

Last Edit: Oct 1, 2017 21:33:02 GMT by Tiago

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